SolveIt is under development
SolveItNCERT · CBSE · NEET
Question 39 / 129 · latest first
✓ Board-verified
Mathematics · 2025 · 1 mark

CBSE 2025 · Region 6 · Set 1 · Q19

Assertion (A): If | a × b |^2+| a · b |^2=256 and | b |=8, then | a |=2 Reason (R): sin^2 θ+ cos^2 θ=1 and | a × b |=| a || b | sin θ and a · b =| a…

Assertion (A): If $\displaystyle |\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}}|^{2}+|\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{b}}|^{2}=256$ and $\displaystyle |\overrightarrow{\mathrm{b}}|=8$, then \[|\overrightarrow{\mathrm{a}}|=2 \] Reason $\displaystyle (R): \quad \sin ^{2} \theta+\cos ^{2} \theta=1$ and \[|\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}}|=|\overrightarrow{\mathrm{a}}||\overrightarrow{\mathrm{b}}| \sin \theta \text { and } \overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{~b}}=|\overrightarrow{\mathrm{a}}||\overrightarrow{\mathrm{b}}| \cos \theta \]
ShareWhatsAppTelegram

More from Vector Algebra

CBSE Class 12 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.