CBSE 2025 · Region 2 · Set 2 · Q19 · 2 marks
When $\displaystyle \mathrm{FeCr}_{2} \mathrm{O}_{4}$ is fused with $\displaystyle \mathrm{Na}_{2} \mathrm{CO}_{3}$ in the presence of air it gives a yellow solution of compound (A). Compound (A) on acidification gives compound (B). Compound (B) on reaction with KCl forms an orange coloured (C). An acidified solution of compound (C) oxidises $\displaystyle \mathrm{Na}_{2} \mathrm{SO}_{3}$ to (D). Identify (A), (B), (C) and (D).
Marking-scheme solution
(A)
= Na2CrO4 / Sodium chromate
(B)
= Na2Cr2O7 / Sodium dichromate
(C)
= K2Cr2O7 / Potassium dichromate
(D)
= Na2SO4 / Sodium sulphate
The d-and f-Block ElementsSome Important Compounds of Transition ElementsAnalysevery_short_answermedium
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CBSE Class 12 Chemistry past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.