CBSE 2026 · Region 5 · Set 3 · Q24 · 3 marks
The rate of a particular reaction quadruples when the temperature increases from $\displaystyle 300$ K to $\displaystyle 320$ K . Calculate the energy of activation $\displaystyle \left(\mathrm{E}_{\mathrm{a}}\right)$ of the reaction assuming that it does not change with temperature. (Given : $\displaystyle \log 4=0 \cdot 60, \mathrm{R}=8 \cdot 314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$ )
Marking-scheme solution
[
]
[
]
T
T
K
Ea
log K
2.303R
T T
−
=
K2 = $\displaystyle 4$ K1
𝑙𝑜𝑔$\displaystyle 4$ =
Ea
[$\displaystyle 320$− $\displaystyle 300$]
[$\displaystyle 300$ ×$\displaystyle 320$ ]
$\displaystyle 0.60$ =
Ea
Ea =
= $\displaystyle 55,143.36$ J mol−$\displaystyle 1$ or $\displaystyle 55.14$ kJ mol−$\displaystyle 1$ .
Chemical KineticsTemperature Dependence of the Rate of a ReactionApplyshort_answermedium
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CBSE Class 12 Chemistry past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.