CBSE 2022 · Region 2 · Set 1 · Q2 · 2 marks
In the given reaction \[\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{NH}_{3}(\mathrm{~g}) \] the rate of formation of $\displaystyle \mathrm{NH}_{3}$ is $\displaystyle 3 \cdot 6 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$. Calculate the(i)rate of reaction, and(ii)rate of disappearance of $\displaystyle \mathrm{H}_{2}(\mathrm{~g})$.
In the given reaction \[\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{NH}_{3}(\mathrm{~g}) \] the rate of formation of $\displaystyle \mathrm{NH}_{3}$ is $\displaystyle 3 \cdot 6 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$.
Calculate the
(i)
rate of reaction, and
(ii)
rate of disappearance of $\displaystyle \mathrm{H}_{2}(\mathrm{~g})$.
Marking-scheme solution
(i) Rate \(\displaystyle =\frac{-\Delta\left(\mathrm{N}_{2}\right)}{\Delta t}=\frac{-1}{3} \frac{\Delta\left(\mathrm{H}_{2}\right)}{\Delta t}=\frac{+1}{2} \frac{\Delta\left(\mathrm{NH}_{3}\right)}{\Delta t}\)
\[\text { Rate }=\frac{1}{2} \times 3 \cdot 6 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}=1 \cdot 8 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}
\]
(ii) \(\displaystyle \frac{-\Delta\left(\mathrm{H}_{2}\right)}{\Delta t}=3 \times 1.8 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}=5.4 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\)
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CBSE Class 12 Chemistry past-paper question from the 2022board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.