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Chemistry · 2025 · 2 marks
CBSE 2025 · Region 4 · Set 1 · Q17
(a) Reactant 'A' underwent a decomposition reaction. The concentration of 'A' was measured periodically and recorded in the table given below: Based…
Reactant 'A' underwent a decomposition reaction. The concentration of 'A' was measured periodically and recorded in the table given below :
Based on the above data, predict the order of the reaction and write the expression for the rate law.
| Time/Hours | [A]/M |
| $\displaystyle 0$ | $\displaystyle 0.40$ |
| $\displaystyle 1$ | $\displaystyle 0.20$ |
| $\displaystyle 2$ | $\displaystyle 0 \cdot 10$ |
| $\displaystyle 3$ | $\displaystyle 0.05$ |
The reaction between $\displaystyle \mathrm{H}_{2}(\mathrm{~g})$ and $\displaystyle \mathrm{I}_{2}(\mathrm{~g})$ was carried out in a sealed isothermal container. The rate law for the reaction was found to be : \[\text { Rate }=\mathrm{k}\left[\mathrm{H}_{2}\right]\left[\mathrm{I}_{2}\right] \] If $\displaystyle 1$ mole of $\displaystyle \mathrm{H}_{2}(\mathrm{~g})$ was added to the reaction chamber and the temperature was kept constant, then predict the change in rate of the reaction and the rate constant.
Marking-scheme solution
Order of the reaction =$\displaystyle 1$ / First
Rate =k[A]
Rate of the reaction will increase.
Rate constant remains same.
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