CBSE 2023 · Region 3 · Set 2 · Q24 · 2 marks
The following data were obtained for the reaction: \[2 \mathrm{NO}_{2}(\mathrm{~g})+\mathrm{F}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{NO}_{2} \mathrm{~F}(\mathrm{~g}) \] Experiment No. $\displaystyle \left[\mathrm{NO}_{2}\right] / \mathrm{M}$ $\displaystyle \left[\mathrm{F}_{2}\right] / \mathrm{M}$ Initial rate $\displaystyle \mathrm{M} \mathrm{min}^{-1}$ $\displaystyle 1$ $\displaystyle 0.2$ $\displaystyle 0.05$ $\displaystyle 6 \times 10^{-3}$ $\displaystyle 2$ $\displaystyle 0.4$ $\displaystyle 0.05$ $\displaystyle 1.2 \times 10^{-2}$ $\displaystyle 3$ $\displaystyle 0.8$ $\displaystyle 0.10$ $\displaystyle 4.8 \times 10^{-2}$
Determine the overall order of reaction.
| Experiment No. | $\displaystyle \left[\mathrm{NO}_{2}\right] / \mathrm{M}$ | $\displaystyle \left[\mathrm{F}_{2}\right] / \mathrm{M}$ | Initial rate $\displaystyle \mathrm{M} \mathrm{min}^{-1}$ |
| $\displaystyle 1$ | $\displaystyle 0.2$ | $\displaystyle 0.05$ | $\displaystyle 6 \times 10^{-3}$ |
| $\displaystyle 2$ | $\displaystyle 0.4$ | $\displaystyle 0.05$ | $\displaystyle 1.2 \times 10^{-2}$ |
| $\displaystyle 3$ | $\displaystyle 0.8$ | $\displaystyle 0.10$ | $\displaystyle 4.8 \times 10^{-2}$ |
Marking-scheme solution
Rate \(\displaystyle =\mathrm{k}\left[\mathrm{NO}_{2}\right]^{\mathrm{p}}\left[\mathrm{F}_{2}\right]^{\mathrm{q}}\)
1. \[6 \times 10^{-3}=\mathrm{k}[0 \cdot 2]^{\mathrm{p}}[0 \cdot 05]^{\mathrm{q}}
\]
2. \[1 \cdot 2 \times 10^{-2}=\mathrm{k}[0 \cdot 4]^{\mathrm{p}}[0 \cdot 05]^{\mathrm{q}}
\]
3. \[4 \cdot 8 \times 10^{-2}=\mathrm{k}[0 \cdot 8]^{\mathrm{p}}[0 \cdot 1]^{\mathrm{q}}
\]
From equation $\displaystyle 1$ and $\displaystyle 2$
\[\mathrm{p}=1
\] From equation $\displaystyle 2$ and $\displaystyle 3$
\[\text { Overall order }=\begin{gathered}
\mathrm{q}=1 \\
\end{gathered}
\]Chemical KineticsFactors Influencing Rate of a ReactionApplyvery_short_answermedium
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CBSE Class 12 Chemistry past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.