CBSE 2023 · Region 5 · Set 2 · Q27 · 3 marks
(a)On the basis of crystal field theory write the electronic configuration for $\displaystyle \mathrm{d}^{5}$ ion with a weak ligand for which $\displaystyle \Delta_{0}<\mathrm{P}$.(b)Explain $\displaystyle \left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}$ is an inner orbital complex whereas $\displaystyle \left[\mathrm{FeF}_{6}\right]^{3-}$ is an outer orbital complex. [Atomic number : $\displaystyle \mathrm{Fe}=26$ ]
(a)
On the basis of crystal field theory write the electronic configuration for $\displaystyle \mathrm{d}^{5}$ ion with a weak ligand for which $\displaystyle \Delta_{0}<\mathrm{P}$.
(b)
Explain $\displaystyle \left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}$ is an inner orbital complex whereas $\displaystyle \left[\mathrm{FeF}_{6}\right]^{3-}$ is an outer orbital complex. [Atomic number : $\displaystyle \mathrm{Fe}=26$ ]
Marking-scheme solution
(a)
\(\displaystyle t_{2 g}{ }^{3} e_{g}{ }^{2}\)
(b)
\(\displaystyle \left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}: \mathrm{CN}^{-}\)is a strong field ligand / \(\displaystyle \mathrm{CN}^{-}\)causes the pairing of the unpaired \(\displaystyle 3 \mathrm{d}\) electrons.
\(\displaystyle \left[\mathrm{FeF}_{6}\right]^{3-}: \mathrm{F}^{-}\)is a weak field ligand / \(\displaystyle \mathrm{F}^{-}\)does not cause the pairing of the 3d electrons.
Coordination CompoundsBonding in Coordination CompoundsUnderstandshort_answerhard
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CBSE Class 12 Chemistry past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.