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Chemistry · 2023 · 3 marks
CBSE 2023 · Region 4 · Set 1 · Q28
Answer any three of the following questions: (a) Explain the type of hybridization in [ Fe ( CN )_6]^3- on the basis of valence bond theory. (Given:…
Answer any three of the following questions :
(a)
Explain the type of hybridization in $\displaystyle \left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}$ on the basis of valence bond theory. (Given : Atomic number of $\displaystyle \mathrm{Fe}=26$ )
(b)
Draw the geometrical isomers of $\displaystyle \left[\mathrm{PtCl}_{2}(\mathrm{en})_{2}\right]^{2+}$ ion.
(c)
$\displaystyle \left[\mathrm{NiCl}_{4}\right]^{2-}$ is paramagnetic while $\displaystyle \left[\mathrm{Ni}(\mathrm{CO})_{4}\right]$ is diamagnetic though both are tetrahedral. Why ?
(d)
Name the type of isomerism when ambidentate ligands are attached to central metal ion. Give one example of ambidentate ligand.
Marking-scheme solution
(a) \(\displaystyle \mathrm{Fe}=3 \mathrm{~d}^{6} 4 \mathrm{~s}^{2}\)
\(\displaystyle 6 \mathrm{CN}^{-}\) Hence hybridization is \(\displaystyle \mathrm{d}^{2} \mathrm{sp}^{3}\)
\(\displaystyle 6 \mathrm{CN}^{-}\) Hence hybridization is \(\displaystyle \mathrm{d}^{2} \mathrm{sp}^{3}\)(b) 
cis
cis(c) \(\displaystyle \mathrm{Cl}^{-}\)being a weak field ligand does not cause pairing of electrons and hence \(\displaystyle \left[\mathrm{NiCl}_{4}\right]^{2-}\) is paramagnetic while CO being a strong field ligand causes pairing of electrons therefore \(\displaystyle \left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\) is diamagnetic.
(d) Linkage isomerism. Example, \(\displaystyle \mathrm{CN}^{-} / \mathrm{NO}_{2}^{-} / \mathrm{SCN}^{-}\)
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CBSE Class 12 Chemistry past-paper question from the 2023 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.