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Chemistry · 2025 · 5 marks
The d-and f-Block ElementsSome Important Compounds of Transition Elements5 marksUnderstandlong answer
CBSE 2025 · Region 6 · Set 1 · Q32
(a) (i) Account for the following: (I) Orange colour of Cr_2 O_7^2- ion changes to yellow when treated with an alkali. (II) Zn, Cd and Hg are…
(i)
Account for the following :
(I)
Orange colour of $\displaystyle \mathrm{Cr}_{2} \mathrm{O}_{7}{ }^{2-}$ ion changes to yellow when treated with an alkali.
(II)
Zn, Cd and Hg are non-transition elements.
(III)
$\displaystyle \mathrm{E}^{\circ}$ value for $\displaystyle \mathrm{Mn}^{3+} / \mathrm{Mn}^{2+}$ couple is highly positive $\displaystyle (+1 \cdot 57 \mathrm{~V})$ as compared to $\displaystyle \mathrm{Cr}^{3+} / \mathrm{Cr}^{2+}$.
(ii)
What happens when :
(I)
Manganate ion undergoes disproportionation reaction in acidic medium ?
(II)
$\displaystyle \mathrm{KMnO}_{4}$ is heated ?
Answer the following questions :
(i)
What is 'Misch metal'? Give its one use.
(ii)
Write the formula of an oxoanion of chromium in which it shows the oxidation state equal to its group number.
(iii)
Why does Vanadium pentoxide $\displaystyle \left(\mathrm{V}_{2} \mathrm{O}_{5}\right)$ act as a catalyst ?
(iv)
Why do transition elements have high enthalpies of atomisation ?
(v)
How do you prepare $\displaystyle \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ from $\displaystyle \mathrm{Na}_{2} \mathrm{CrO}_{4}$ ?
Marking-scheme solution
(a)(i)
(I)
Due to formation of chromate /CrO42- ion
(II)
Due to completely filled d-orbitals in ground state as well as oxidised state.
(III)
Because Mn2+ is more stable due to stable 3d5 configuration whereas Cr3+ is more stable due
to stable t2g3 configuration.
(ii)
(I)
it changes to permanaganate ion / MnO4- is formed /
(II)
Potassium manganate/ K2MnO4 is formed /
(b)
i)
•
An alloy of lanthanoid / an alloy of lanthanoid and iron with traces of S, C, Ca and Al.
•
used in making bullets/shells/ lighter flint
(ii)
CrO42-/ Cr2O72-
(iii)
variable oxidation state of vanadium / large surface area /Complex formation
(iv)
Because of large number of unpaired electrons in their atoms they have stronger interatomic
interaction or strong metallic bonding
(v)
by acidification of Na2CrO4/
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CBSE Class 12 Chemistry past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.