Account for the following: (i) Cr^2+ is a strong reducing agent. (ii) Ti^3+ is coloured whereas Sc^3+ is colourless in aqueous solution. (iii) Zn, Cd…

Because Cr is more stable in +3 oxidation state due to stable t 2 g^3 configuration Because of the presence of unpaired electron in 3d-orbital of Ti^3+ whereas Sc^3+ has no unpaired electron / Ti^3+ shows d-d transition while Sc^3+ does not. Because of completely filled d -orbital in the ground state or in any of its oxidation state.

CBSE 2022 · Region 3 · Set 2 · Q4 · 3 marks

Account for the following :
(i)
$\displaystyle \mathrm{Cr}^{2+}$ is a strong reducing agent.
(ii)
$\displaystyle \mathrm{Ti}^{3+}$ is coloured whereas $\displaystyle \mathrm{Sc}^{3+}$ is colourless in aqueous solution.
(iii)
Zn, Cd and Hg are not called transition elements.

The d-and f-Block ElementsGeneral Properties of the Transition Elements (d-Block)Understandshort_answermedium

Practice The d-and f-Block Elements →All The d-and f-Block Elements questions

Account for the following :
(i)
$\displaystyle \mathrm{Cr}^{2+}$ is a strong reducing agent.
(ii)
$\displaystyle \mathrm{Ti}^{3+}$ is coloured whereas $\displaystyle \mathrm{Sc}^{3+}$ is colourless in aqueous solution.
(iii)
Zn, Cd and Hg are not called transition elements.

Marking-scheme solution

More from The d-and f-Block Elements

Account for the following :(i)$\displaystyle \mathrm{Cr}^{2+}$ is a strong reducing agent.(ii)$\displaystyle \mathrm{Ti}^{3+}$ is coloured whereas $\displaystyle \mathrm{Sc}^{3+}$ is colourless in aqueous solution.(iii)Zn, Cd and Hg are not called transition elements.

Marking-scheme solution

More from The d-and f-Block Elements

Account for the following :
(i)
$\displaystyle \mathrm{Cr}^{2+}$ is a strong reducing agent.
(ii)
$\displaystyle \mathrm{Ti}^{3+}$ is coloured whereas $\displaystyle \mathrm{Sc}^{3+}$ is colourless in aqueous solution.
(iii)
Zn, Cd and Hg are not called transition elements.