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Chemistry · 2023 · 2 marks
CBSE 2023 · Region 1 · Set 2 · Q19
A solution is prepared by dissolving 10 g of non-volatile solute in 200 g of water. It has a vapour pressure of 31.84 mm Hg at 308 K. Calculate the…
A solution is prepared by dissolving $\displaystyle 10$ g of non-volatile solute in $\displaystyle 200$ g of water. It has a vapour pressure of $\displaystyle 31.84$ mm Hg at $\displaystyle 308$ K. Calculate the molar mass of the solute. (Vapour pressure of pure water at $\displaystyle 308 \mathrm{~K}=32 \mathrm{~mm} \mathrm{Hg}$ ) $\displaystyle 2$
Marking-scheme solution
\[\frac{p^{0}-p_{A}}{P A^{0}}=\frac{\dfrac{W_{A}}{M_{A}}}{\dfrac{W_{A}}{M_{A}}+\dfrac{W_{B}}{M_{B}}}=\frac{\dfrac{W_{B}}{M_{B}}}{\dfrac{W_{A}}{M_{A}}}
\]
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CBSE Class 12 Chemistry past-paper question from the 2023 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.