Three resistors of 2 Ω, 3 Ω and 6 Ω are connected in (i) series, and (ii) parallel. Draw the arrangements of the resistors and find the equivalent…

In series, \(\displaystyle \mathrm{R}_{\mathrm{s}}=\mathrm{R}_{1}+\mathrm{R}_{2}+\mathrm{R}_{3}\)

\[=(2+3+6) \Omega=11 \Omega \]

In parallel,

\[\begin{aligned} \frac{1}{R_{p}} & =\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}} \\ & =\frac{1}{2}+\frac{1}{3}+\frac{1}{6} \\ & =\frac{3+2+1}{6} \\ & R_{p}=1 \cdot 0 \Omega \end{aligned} \]