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Science · 2024 · 2 marks
CBSE 2024 · Region 1 · Set 1 · Q25
Show how you would connect three resistors each of resistance $\displaystyle 6 \Omega$, so that the combination has a resistance of $\displaystyle 9 \Omega$. Also justify your answer.In the given circuit calculate the power consumed in watts in the resistor of $\displaystyle 2 \Omega$ :
Show how you would connect three resistors each of resistance $\displaystyle 6 \Omega$, so that the combination has a resistance of $\displaystyle 9 \Omega$. Also justify your answer.
In the given circuit calculate the power consumed in watts in the resistor of $\displaystyle 2 \Omega$ :
Marking-scheme solution
(A)
When two \(\displaystyle 6 \Omega\) resistances are connected in parallel and the third resistance of \(\displaystyle 6 \Omega\) is connected in series combinations to this, then equivalent resistance will be \(\displaystyle 9 \Omega /\)
(B)
Equivalent resistance \(\displaystyle =R_{1}+R_{2}=1 \Omega+2 \Omega=3 \Omega\)
\[\begin{aligned}
& I=\frac{\mathrm{V}^{7}}{{ }_{6 \mathrm{~V}}} \\
& =\frac{6 \mathrm{~V}}{1 \Omega+2 \Omega}=\frac{6 \mathrm{~V}}{3 \Omega}=2 \mathrm{~A}
\end{aligned}
\]
Electric power, \(\displaystyle \mathrm{P}=\mathrm{I}^{2} \mathrm{R}\)
\[=(2 \mathrm{~A})^{2} \times 2 \Omega=4 \times 2 \mathrm{~W}=8 \mathrm{~W}
\]
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CBSE Class 10 Science past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.