CBSE 2025 · Region 2 · Set 1 · Q26 · 2 marks
An electric kettle is rated $\displaystyle 750$ W; $\displaystyle 220$ V. Can this kettle be used in a circuit which has a fuse of current rating $\displaystyle 3$ A ? Give reason for your answer.
Marking-scheme solution
\(\displaystyle \mathrm{P}=750 \mathrm{~W}, \mathrm{~V}=220 \mathrm{~V}\)
Current drawn by kettle, \(\displaystyle \mathrm{I}=\frac{\mathrm{P}}{\mathrm{V}}\)
\[\begin{gathered}
=750 \mathrm{~W} / 220 \mathrm{~V} \\
=3.4 \mathrm{~A}
\end{gathered}
\]
No, this kettle cannot be used.
The current drawn by the kettle is more than the fuse rating (3A). So, the fuse will melt and break the circuit.
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