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Mathematics · 2026 · 4 marks
CBSE 2026 · Region 4 · Set 1 · Q38
Observe the map of Jaipur city placed on a Cartesian plane. Taking Rambagh Palace as origin, the location of some places are given below : Point A : $\displaystyle (-4,2)$ Rajasthan High Court Point B : $\displaystyle (4, -4)$ Birla Mandir Point C : $\displaystyle (4,3)$ Heera Bagh Point D : $\displaystyle (-5, -2)$ Amar Jawan Jyoti Based on the above, answer the following questions :(i)Advocate Rehana stays at Heera Bagh. How much distance she has to cover daily to go to the court and coming back home ?(ii)There is a crossing on X-axis which divides AD in a certain ratio. Find the ratio.(iii)Is Birla Mandir equidistant from Heera Bagh and Amar Jawan Jyoti ? Justify your answer.Using section formula, show that points A , O and B are not collinear. $\displaystyle 1171$-$\displaystyle 1$ { } of $\displaystyle 24$
Observe the map of Jaipur city placed on a Cartesian plane. Taking Rambagh Palace as origin, the location of some places are given below : Point A : $\displaystyle (-4,2)$ Rajasthan High Court Point B : $\displaystyle (4, -4)$ Birla Mandir Point C : $\displaystyle (4,3)$ Heera Bagh Point D : $\displaystyle (-5, -2)$ Amar Jawan Jyoti Based on the above, answer the following questions :
(i)
Advocate Rehana stays at Heera Bagh. How much distance she has to cover daily to go to the court and coming back home ?
(ii)
There is a crossing on X-axis which divides AD in a certain ratio. Find the ratio.
(iii)
Is Birla Mandir equidistant from Heera Bagh and Amar Jawan Jyoti ? Justify your answer.
Using section formula, show that points A , O and B are not collinear. $\displaystyle 1171$-$\displaystyle 1$ { } of $\displaystyle 24$
Marking-scheme solution
(i) Distance travelled \(\displaystyle =2 \mathrm{AC}\)
\[\begin{aligned}
& =2 \sqrt{(-4-4)^{2}+(2-3)^{2}} \\
& =2 \sqrt{64+1} \\
& =2 \sqrt{65}
\end{aligned}
\]
Hence, required distance is \(\displaystyle 2 \sqrt{65}\) units.(ii) Let the point \(\displaystyle \mathrm{P}(x, 0)\) divides AD in the ratio \(\displaystyle \mathrm{K}: 1\)
\[\therefore \mathrm{AP}: \mathrm{PD}=\mathrm{K}: 1
\]
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CBSE Class 10 Mathematics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.