CBSE 2025 · Region 5 · Set 1 · Q22 · 2 marks
The coordinates of the end points of the line segment AB are A$\displaystyle (-2, -2)$ and $\displaystyle \mathrm{B}(2,-4)$. P is the point on AB such that $\displaystyle \mathrm{BP}=\frac{4}{7} \mathrm{AB}$. Find the coordinates of point P.
Marking-scheme solution
P (x, y) divides AB in the ratio $\displaystyle 3$: $\displaystyle 4$
\[\begin{aligned}
& x=\frac{3 \times 2+4 \times(-2)}{4+3} \Rightarrow x=-\frac{2}{7} \\
& y=\frac{3 \times(-4)+4 \times(-2)}{4+3} \Rightarrow y=-\frac{20}{7}
\end{aligned}
\] ∴ Coordinates of P are \(\displaystyle \left(-\frac{2}{7},-\frac{20}{7}\right)\)Coordinate GeometrySection FormulaApplyvery_short_answermedium
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CBSE Class 10 Mathematics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.