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Mathematics · 2024 · 2 marks
CBSE 2024 · Region 1 · Set 1 · Q24
In the given figure, ABCD is a quadrilateral. Diagonal BD bisects $\displaystyle \angle \mathrm{B}$ and $\displaystyle \angle \mathrm{D}$ both. Prove that :
Marking-scheme solution
(i) In \(\displaystyle \triangle \mathrm{ABD}\) & \(\displaystyle \triangle \mathrm{CBD}\)
\[\begin{aligned}
& \angle 3=\angle 4 \\
& \angle 1=\angle 2
\end{aligned}
\]
(ii) \(\displaystyle \triangle \mathrm{ABD} \cong \triangle \mathrm{CBD}\)
\(\displaystyle \therefore \mathrm{AB}=\mathrm{BC}\)
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CBSE Class 10 Mathematics past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.