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Mathematics · 2024 · 2 marks
CBSE 2024 · Region 3 · Set 1 · Q24
In the given figure, EA/EC=EB/ED, prove that Δ EAB ∼ Δ ECD
In the given figure, $\displaystyle \frac{\mathrm{EA}}{\mathrm{EC}}=\frac{\mathrm{EB}}{\mathrm{ED}}$, prove that $\displaystyle \Delta \mathrm{EAB} \sim \Delta \mathrm{ECD}$
Marking-scheme solution
In \(\displaystyle \triangle \mathrm{EAB}\) and \(\displaystyle \triangle \mathrm{ECD}\)
\[\begin{aligned}
& \frac{\mathrm{EA}}{\mathrm{EC}}=\frac{\mathrm{EB}}{\mathrm{ED}} \\
& \angle \mathrm{AEB}=\angle \mathrm{CED} \\
& \Delta \mathrm{EAB} \sim \triangle \mathrm{ECD}
\end{aligned}
\]
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CBSE Class 10 Mathematics past-paper question from the 2024 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.