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Mathematics · 2025 · 1 mark

CBSE 2025 · Region 6 · Set 1 · Q12

If x((2 tan 30^°)/(1+ tan^2 30^°))=y((2 tan 30^°)/(1- tan^2 30^°)), then x: y=

If $\displaystyle x\left(\frac{2 \tan 30^{\circ}}{1+\tan ^{2} 30^{\circ}}\right)=y\left(\frac{2 \tan 30^{\circ}}{1-\tan ^{2} 30^{\circ}}\right)$, then $\displaystyle x: y=$
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