CBSE 2025 · Region 6 · Set 1 · Q12 · 1 mark
If $\displaystyle x\left(\frac{2 \tan 30^{\circ}}{1+\tan ^{2} 30^{\circ}}\right)=y\left(\frac{2 \tan 30^{\circ}}{1-\tan ^{2} 30^{\circ}}\right)$, then $\displaystyle x: y=$
Official answer
From CBSE’s own marking scheme for this paper.
(C)
$\displaystyle 2$ : $\displaystyle 1$
Introduction to TrigonometryTrigonometric Ratios of Some Specific AnglesApplymcqmedium
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CBSE Class 10 Mathematics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.