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Mathematics · 2025 · 1 mark
CBSE 2025 · Region 6 · Set 2 · Q12
If x= cos 30^°- sin 30^° and y = tan 60^°- cot 60^°, then
If $\displaystyle x=\cos 30^{\circ}-\sin 30^{\circ}$ and $\displaystyle \mathrm{y}=\tan 60^{\circ}-\cot 60^{\circ}$, then
Official answer
(C)
$\displaystyle x<\mathrm{y}$
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CBSE Class 10 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.