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Mathematics · 2025 · 2 marks
CBSE 2025 · Region 2 · Set 1 · Q21
If p and q are zeroes of the polynomial p ( y )=21 y^2- y -2, then find the value of (1- p ).(1- q ).
If p and q are zeroes of the polynomial $\displaystyle \mathrm{p}(\mathrm{y})=21 \mathrm{y}^{2}-\mathrm{y}-2$, then find the value of $\displaystyle (1-\mathrm{p}) .(1-\mathrm{q})$.
Marking-scheme solution
\[\begin{aligned}
& p+q=\frac{1}{21} \\
& p \cdot q=\frac{-2}{21} \\
& \begin{aligned}
(1-p)(1-q) & =1-(p+q)+p q \\
& =1-\frac{1}{21}-\frac{2}{21} \\
& =\frac{18}{21} \text { or } \frac{6}{7}
\end{aligned}
\end{aligned}
\]
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CBSE Class 10 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.