CBSE 2025 · Region 1 · Set 1 · Q22 · 2 marks
Find the zeroes of the polynomial $\displaystyle \mathrm{p}(\mathrm{x})=\mathrm{x}^{2}+\frac{4}{3} \mathrm{x}-\frac{4}{3}$.
Marking-scheme solution
\[\begin{aligned}
& \frac{1}{3}\left(3 x^{2}+4 x-4\right) \\
= & \frac{1}{3}\left(3 x^{2}+6 x-2 x-4\right) \\
= & \frac{1}{3}(3 x-2)(x+2)
\end{aligned}
\]
Zeroes are \(\displaystyle \frac{2}{3}\), -$\displaystyle 2$
PolynomialsGeometrical Meaning of the Zeroes of a PolynomialApplyvery_short_answereasy
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CBSE Class 10 Mathematics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.