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Mathematics · 2026 · 2 marks
CBSE 2026 · Region 1 · Set 2 · Q25
Find the zeroes of the quadratic polynomial $\displaystyle x^{2}+7 x+10$, and verify the relationship between the zeroes and its coefficients.
Marking-scheme solution
\[x^{2}+7 x+10=(x+2)(x+5)
\]
So, the zeroes of the polynomial are -$\displaystyle 2$ and -$\displaystyle 5$
Sum of zeroes \(\displaystyle =-7=\frac{-7}{1}=-\frac{\text { coefficient of } x}{\text { coeffiecient of } x^{2}}\)
Product of zeroes \(\displaystyle =10=\frac{10}{1}=\frac{\text { constant term }}{\text { coefficient of } x^{2}}\)
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CBSE Class 10 Mathematics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.