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Mathematics · 2026 · 2 marks
CBSE 2026 · Region 4 · Set 1 · Q25
α and β are the zeroes of the polynomial 5 x^2-16 x-10. Find the value of (α)/(β)+(β)/(α).
$\displaystyle \alpha$ and $\displaystyle \beta$ are the zeroes of the polynomial $\displaystyle 5 x^{2}-16 x-10$. Find the value of $\displaystyle \frac{\alpha}{\beta}+\frac{\beta}{\alpha}$.
Marking-scheme solution
\(\displaystyle \alpha+\beta=\frac{16}{5}, \alpha \beta=-2\)
\(\displaystyle \therefore \frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{(\alpha+\beta)^{2}-2 \alpha \beta}{\alpha \beta}=\frac{\left(\dfrac{16}{5}\right)^{2}+4}{-2}\)
\[=-\frac{356}{50} \text { or }-\frac{178}{25}
\]
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CBSE Class 10 Mathematics past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.