Physics · 2020
NEET 2020 · 14 October · Code Z6 · Q97
What is the depth at which the value of acceleration due to gravity becomes 1 / n times the value that at the surface of earth? (radius of earth =R )
What is the depth at which the value of acceleration due to gravity becomes $\displaystyle 1 / n$ times the value that at the surface of earth ? (radius of earth $\displaystyle =R$ )
Official answer
(1)
$\displaystyle R(n-1) / n$
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