Physics · 2021
NEET 2021 · 12 September · Code M1 · Q42
A particle of mass 'm' is projected with a velocity v= kV_e ( k <1) from the surface of the earth. ( V_e =. escape velocity ) The maximum height…
A particle of mass 'm' is projected with a velocity $\displaystyle v=\mathrm{kV}_{\mathrm{e}}(\mathrm{k}<1)$ from the surface of the earth.
$\displaystyle \left(\mathrm{V}_{\mathrm{e}}=\right.$ escape velocity $\displaystyle )$
The maximum height above the surface reached by the particle is :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \frac{\mathrm{Rk}^2}{1-\mathrm{k}^2}$
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NEET (UG) 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.