Physics · 2009
NEET 2009 · Prelims · Code A · Q15
The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T_1 and T_2( T_1> T_2). The rate of heat…
The two ends of a rod of length $\displaystyle L$ and a uniform cross-sectional area A are kept at two temperatures $\displaystyle \mathrm{T}_1$ and $\displaystyle \mathrm{T}_2\left(\mathrm{~T}_1>\mathrm{T}_2\right)$. The rate of heat transfer, $\displaystyle \frac{\mathrm{dQ}}{\mathrm{dt}}$, through the rod in a steady state is given by :
Official answer
(1)
$\displaystyle \frac{\mathrm{dQ}}{\mathrm{dt}}=\frac{\mathrm{kA}\left(\mathrm{T}_1-\mathrm{T}_2\right)}{\mathrm{L}}$
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NEET (UG) 2009 Physics question, with the answer from NTA’s final answer key. Where our answers come from.