Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be: [Take specific…

Steam at $\displaystyle 100$°C is passed into $\displaystyle 20$ g of water at $\displaystyle 10$°C. When water acquires a temperature of $\displaystyle 80$°C, the mass of water present will be : [Take specific heat of water $\displaystyle =1 \mathrm{cal} \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}$ and latent heat of steam $\displaystyle =540 \mathrm{cal} \mathrm{g}^{-1}$]