Physics · 2014
NEET 2014 · 4 May · Code P · Q42
The Binding energy per nucleon of _3^7 Li and _2^4 He nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction _3^7 Li +_1^1 H →_2^4…
The Binding energy per nucleon of $\displaystyle { }_3^7 \mathrm{Li}$ and $\displaystyle { }_2^4 \mathrm{He}$ nuclei are $\displaystyle 5.60$ MeV and $\displaystyle 7.06$ MeV, respectively. In the nuclear reaction $\displaystyle { }_3^7 \mathrm{Li}+{ }_1^1 \mathrm{H} \rightarrow{ }_2^4 \mathrm{He}+{ }_2^4 \mathrm{He}+\mathrm{Q}$, the value of energy Q released is :
Official answer
From NTA’s final answer key for this paper.
(4)
17.$\displaystyle 3$ MeV
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