Consider the following nuclear reaction: ^238 U →^234 Th+^4 He Take masses of ^238 U,^234 Th and ^4 He as 238.050 u, 234.043 u and 4.003 u,…

Consider the following nuclear reaction : $$ { }^{238} \mathrm{U} \rightarrow{ }^{234} \mathrm{Th}+{ }^4 \mathrm{He}Take masses of $\displaystyle { }^{238} \mathrm{U},{ }^{234} \mathrm{Th}$ and $\displaystyle { }^4 \mathrm{He}$ as $\displaystyle 238.050$ u, $\displaystyle 234.043$ u and $\displaystyle 4.003$ u, respectively. The Q value for the reaction, in keV, is : [Given : $\displaystyle 1 \mathrm{u}=931.5 \mathrm{MeV} \mathrm{c}^{-2}$ ]