_82^290 X → α Y → e^+ Z → β^- P → e^- Q In the nuclear emission stated above, the mass number and atomic number of the product Q respectively, are:

$\displaystyle { }_{82}^{290} X \xrightarrow{\alpha} Y \xrightarrow{e^{+}} Z \xrightarrow{\beta^{-}} P \xrightarrow{e^{-}} Q$ In the nuclear emission stated above, the mass number and atomic number of the product $\displaystyle Q$ respectively, are :