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Physics · 2026 · 4 marks
NEET 2026 · 3 May · Code 11 · Q10
In the first excited state of hydrogen atom, the energy of its electron is -3.4 eV. The radial distance of the electron from the hydrogen nucleus in…
In the first excited state of hydrogen atom, the energy of its electron is $\displaystyle -3.4 \mathrm{eV}$. The radial distance of the electron from the hydrogen nucleus in this case is approximately :
(Take $\displaystyle 1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J}, \mathrm{e}=1.6 \times 10^{-19} \mathrm{C}$ and $\displaystyle \frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 \mathrm{~N} \mathrm{~m}^2 / \mathrm{C}^2$ )
Official answer
From NTA’s provisional answer key for this paper. NTA published no final key for it.
(3)
$\displaystyle 2.1 \times 10^{-10} \mathrm{~m}$
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NEET (UG) 2026 Physics question, with the answer from NTA’s provisional answer key. Where our answers come from.