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Physics · 2026 · 4 marks
NEET 2026 · 21 June · Code 50 · Q40
Consider that an electron is revolving in an excited state of Hydrogen atom with velocity √25.6 × 10^5 ms^-1. The radius of the orbit is x × 10^-9 m.…
Consider that an electron is revolving in an excited state of Hydrogen atom with velocity $\displaystyle \sqrt{25.6} \times 10^5 \mathrm{~ms}^{-1}$. The radius of the orbit is $\displaystyle x \times 10^{-9} \mathrm{~m}$. The value of $\displaystyle x$ is :
[Take the mass of electron to be $\displaystyle 9 \times 10^{-31} \mathrm{~kg}$, charge of electron $\displaystyle =-1.6 \times 10^{-19} \mathrm{C}$ and $\displaystyle \frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \mathrm{~N}$ $\displaystyle \mathrm{m}^2 \mathrm{C}^{-2}$ ]
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 1$
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