Physics · 2016
NEET 2016 · 24 July · Code AA · Q39
Electrons of mass m with de-Broglie wavelength λ fall on the target in an X-ray tube. The cutoff wavelength (λ_0) of the emitted X-ray is
Electrons of mass $\displaystyle m$ with de-Broglie wavelength $\displaystyle \lambda$ fall on the target in an X-ray tube. The cutoff wavelength $\displaystyle \left(\lambda_0\right)$ of the emitted X-ray is
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \lambda_0=\frac{2 m c \lambda^2}{h}$
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NEET (UG) 2016 Physics question, with the answer from NTA’s final answer key. Where our answers come from.