Physics · 2019
NEET 2019 · 5 May · Code P1 · Q13
An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, (nearly): ( m_e =9 × 10^-31 kg )
An electron is accelerated through a potential difference of $\displaystyle 10,000 \mathrm{~V}$. Its de Broglie wavelength is, (nearly) : $\displaystyle \left(\mathrm{m}_{\mathrm{e}}=9 \times 10^{-31} \mathrm{~kg}\right)$
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 12.2 \times 10^{-12} \mathrm{~m}$
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