Physics · 2010
NEET 2010 · Prelims · Code A · Q45
An alpha nucleus of energy 1/2 m v^2 bombards a heavy nuclear target of charge Z e. Then the distance of closest approach for the alpha nucleus will…
An alpha nucleus of energy $\displaystyle \frac{1}{2} m v^2$ bombards a heavy nuclear target of charge $\displaystyle Z \mathrm{e}$. Then the distance of closest approach for the alpha nucleus will be proportional to :
Official answer
(4)
$\displaystyle \frac{1}{\mathrm{~m}}$
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NEET (UG) 2010 Physics question, with the answer from NTA’s final answer key. Where our answers come from.