Physics · 2012
NEET 2012 · Mains · Code C · Q61
A magnetic needle suspended parallel to a magnetic field requires √ 3 J of work to turn it through 60^°. The torque needed to maintain the needle in…
A magnetic needle suspended parallel to a magnetic field requires $\displaystyle \sqrt{3} \mathrm{~J}$ of work to turn it through $\displaystyle 60^{\circ}$. The torque needed to maintain the needle in this position will be :
Official answer
(4)
$\displaystyle 3$ J
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NEET (UG) 2012 Physics question, with the answer from NTA’s final answer key. Where our answers come from.