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Physics · 2019

NEET 2019 · 5 May · Code P1 · Q26

At a point A on the earth's surface the angle of dip, δ=+25^°. At a point B on the earth's surface the angle of dip, δ=-25^°. We can interpret that:

At a point A on the earth's surface the angle of $\displaystyle \operatorname{dip}, \delta=+25^{\circ}$. At a point $\displaystyle B$ on the earth's surface the angle of dip, $\displaystyle \delta=-25^{\circ}$. We can interpret that :
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NEET (UG) 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.