Physics · 2019
NEET 2019 · 5 May · Code P1 · Q22
A force F =20+10 y acts on a particle in y -direction where F is in newton and y in meter. Work done by this force to move the particle from y=0 to…
A force $\displaystyle \mathrm{F}=20+10 y$ acts on a particle in $\displaystyle y$-direction where F is in newton and $\displaystyle y$ in meter. Work done by this force to move the particle from $\displaystyle y=0$ to $\displaystyle y=1 \mathrm{~m}$ is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 25$ J
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NEET (UG) 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.