An electric lift with a maximum load of 2000 kg (lift + passengers) is moving up with a constant speed of 1.5 ms^-1. The frictional force opposing…

An electric lift with a maximum load of $\displaystyle 2000$ kg (lift + passengers) is moving up with a constant speed of $\displaystyle 1.5 \mathrm{~ms}^{-1}$. The frictional force opposing the motion is $\displaystyle 3000$ N. The minimum power delivered by the motor to the lift in watts is : $\displaystyle \left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)$