Chemistry · 2008
NEET 2008 · Prelims · Code A · Q53
The value of equilibrium constant of the reaction HI ( g ) ⇌ 1/2 H_2( g )+1/2 I_2 is 8.0 The equilibrium constant of the reaction H_2( g )+ I_2( g )…
The value of equilibrium constant of the reaction $\displaystyle \mathrm{HI}(\mathrm{g}) \rightleftharpoons \frac{1}{2} \mathrm{H}_2(\mathrm{~g})+\frac{1}{2} \mathrm{I}_2$ is $\displaystyle 8.0$
The equilibrium constant of the reaction $\displaystyle \mathrm{H}_2(\mathrm{~g})+\mathrm{I}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{g})$ will be :
Official answer
(3)
$\displaystyle \frac{1}{64}$
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NEET (UG) 2008 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.