Chemistry · 2020
NEET 2020 · 13 September · Code E1 · Q92
Find out the solubility of Ni ( OH )_2 in 0.1 M NaOH. Given that the ionic product of Ni ( OH )_2 is 2 × 10^-15.
Find out the solubility of $\displaystyle \mathrm{Ni}(\mathrm{OH})_2$ in $\displaystyle 0.1$ M NaOH. Given that the ionic product of $\displaystyle \mathrm{Ni}(\mathrm{OH})_2$ is $\displaystyle 2 \times 10^{-15}$.
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 2 \times 10^{-13} \mathrm{M}$
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