3 O_2( g ) ⇌ 2 O_3( g ) for the above reaction at 298 K, K_c is found to be 3.0 × 10^-59. If the concentration of O_2 at equilibrium is 0.040 M then…

$\displaystyle 3 \mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{O}_3(\mathrm{~g})$ for the above reaction at $\displaystyle 298 \mathrm{~K}, \mathrm{~K}_{\mathrm{c}}$ is found to be $\displaystyle 3.0 \times 10^{-59}$. If the concentration of $\displaystyle \mathrm{O}_2$ at equilibrium is $\displaystyle 0.040$ M then concentration of $\displaystyle \mathrm{O}_3$ in M is