Chemistry · 2018
NEET 2018 · 6 May · Code AA · Q77
The solubility of BaSO_4 in water is 2.42 × 10^-3 gL^-1 at 298 K. The value of its solubility product ( K_sp ) will be (Given molar mass of…
The solubility of $\displaystyle \mathrm{BaSO}_4$ in water is $\displaystyle 2.42 \times 10^{-3} \mathrm{gL}^{-1}$ at $\displaystyle 298$ K. The value of its solubility product $\displaystyle \left(\mathrm{K}_{\mathrm{sp}}\right)$ will be
(Given molar mass of $\displaystyle \mathrm{BaSO}_4=233 \mathrm{~g} \mathrm{~mol}^{-1}$)
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 1.08 \times 10^{-10} \mathrm{~mol}^2 \mathrm{~L}^{-2}$
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NEET (UG) 2018 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.