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Chemistry · 2008
NEET 2008 · Prelims · Code A · Q68
The dissociation equilibrium of a gas AB_2 can be represented as: 2 AB_2( g ) ⇌ 2 AB ( g )+ B_2( g ) The degree of dissociation is ' x ' and is small…
The dissociation equilibrium of a gas $\displaystyle \mathrm{AB}_2$ can be represented as :
$$2 \mathrm{AB}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{AB}(\mathrm{~g})+\mathrm{B}_2(\mathrm{~g})
$$
The degree of dissociation is '$\displaystyle x$' and is small compared to 1. The expression relating the degree of dissociation ($\displaystyle x$) with equilibrium constant $\displaystyle \mathrm{K}_{\mathrm{P}}$ and total pressure P is :
Official answer
(3)
$\displaystyle \left(2 \mathrm{~K}_{\mathrm{P}} / \mathrm{P}\right)^{1 / 3}$
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NEET (UG) 2008 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.