Chemistry · 2019
NEET 2019 · 5 May · Code P1 · Q62
pH of a saturated solution of Ca ( OH )_2 is 9. The solubility product ( K_sp ) of Ca ( OH )_2 is:
pH of a saturated solution of $\displaystyle \mathrm{Ca}(\mathrm{OH})_2$ is 9. The solubility product $\displaystyle \left(\mathrm{K}_{\mathrm{sp}}\right)$ of $\displaystyle \mathrm{Ca}(\mathrm{OH})_2$ is :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 0.5 \times 10^{-15}$
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