Chemistry · 2012
NEET 2012 · Prelims · Code A · Q59
pH of a saturated solution of Ba ( OH )_2 is 12. The value of solubility product ( K_SP ) of Ba ( OH )_2 is:
pH of a saturated solution of $\displaystyle \mathrm{Ba}(\mathrm{OH})_2$ is 12. The value of solubility product $\displaystyle \left(\mathrm{K}_{\mathrm{SP}}\right)$ of $\displaystyle \mathrm{Ba}(\mathrm{OH})_2$ is :
Official answer
(4)
$\displaystyle 5.0 \times 10^{-7}$
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