Chemistry · 2010
NEET 2010 · Mains · Code C · Q101
Consider the following relations for emf of an electrochemical cell (a) emf of cell = (Oxidation potential of anode) - (Reduction potential of…
Consider the following relations for emf of an electrochemical cell
(a)
emf of cell = (Oxidation potential of anode) - (Reduction potential of cathode)
(b)
emf of cell = (Oxidation potential of anode) + (Reduction potential of cathode)
(c)
emf of cell = (Reduction potential of anode) + (Reduction potential of cathode)
(d)
emf of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)
Which of the above relations are correct?
Options:
Official answer
(4)
(b) and (d)
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