SolveItClass 10 · NCERT

NCERT Solutions · Class 10 Mathematics Polynomials

3 questions · 3 still being checked

EXERCISE 2.2 1–2 (part 2 of 2)

  1. Exercise 1

    Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.
    (i)
    x22x8\displaystyle x^{2}-2 x-8
    (ii)
    4s24s+1\displaystyle 4 s^{2}-4 s+1
    (iii)
    6x237x\displaystyle 6 x^{2}-3-7 x
    (iv)
    4u2+8u\displaystyle 4 u^{2}+8 u
    (v)
    t215\displaystyle t^{2}-15
    (vi)
    3x2x4\displaystyle 3 x^{2}-x-4
    NCERT’s answer
    (i)
    -$\displaystyle 2,4$ (ii) $\displaystyle \frac{1}{2}, \frac{1}{2}$ (iii) $\displaystyle -\frac{1}{3}, \frac{3}{2}$ (iv) -$\displaystyle 2,0$ (v) $\displaystyle -\sqrt{15}, \sqrt{15}$ (vi) $\displaystyle -1, \frac{4}{3}$

    Working being prepared

  2. Exercise 2

    Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively.
    (i)
    14,1\displaystyle \frac{1}{4},-1
    (ii)
    2,13\displaystyle \sqrt{2}, \frac{1}{3}
    (iii)
    0,5\displaystyle 0, \sqrt{5}
    (iv)
    1,1\displaystyle 1,1
    (v)
    14,14\displaystyle -\frac{1}{4}, \frac{1}{4}
    (vi)
    4,1\displaystyle 4,1
    NCERT’s answer
    (i)
    $\displaystyle 4 x^{2}-x-4$ (ii) $\displaystyle 3 x^{2}-3 \sqrt{2} x+1$ (iii) $\displaystyle x^{2}+\sqrt{5}$ (iv) $\displaystyle x^{2}-x+1$ (v) $\displaystyle 4 x^{2}+x+1$ (vi) $\displaystyle x^{2}-4 x+1$

    Working being prepared