SolveItClass 10 · NCERT

NCERT Solutions · Class 10 Mathematics Arithmetic Progressions

49 questions · 49 still being checked

EXERCISE 5.3 11–20 (part 5 of 6)

  1. Exercise 11

    If the sum of the first n\displaystyle n terms of an AP is 4nn2\displaystyle 4 n-n^{2}, what is the first term (that is S1\displaystyle \mathrm{S}_{1} )? What is the sum of first two terms? What is the second term? Similarly, find the 3rd, the 10th and the n\displaystyle nth terms.
    NCERT’s answer
    $\displaystyle \mathrm{S}_{1}=3, \mathrm{~S}_{2}=4 ; a_{2}=\mathrm{S}_{2}-\mathrm{S}_{1}=1 ; \mathrm{S}_{3}=3, a_{3}=\mathrm{S}_{3}-\mathrm{S}_{2}=-1$, $\displaystyle a_{10}=\mathrm{S}_{10}-\mathrm{S}_{9}=-15 ; a_{n}=\mathrm{S}_{n}-\mathrm{S}_{n-1}=5-2 n$.

    Working being prepared

  2. Exercise 12

    Find the sum of the first 40\displaystyle 40 positive integers divisible by 6.
    NCERT’s answer
    $\displaystyle 4920$

    Working being prepared

  3. Exercise 13

    Find the sum of the first 15\displaystyle 15 multiples of 8.
    NCERT’s answer
    $\displaystyle 960$

    Working being prepared

  4. Exercise 14

    Find the sum of the odd numbers between 0\displaystyle 0 and 50.
    NCERT’s answer
    $\displaystyle 625$

    Working being prepared

  5. Exercise 15

    A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: ₹ 200\displaystyle 200 for the first day, ₹ 250\displaystyle 250 for the second day, ₹ 300\displaystyle 300 for the third day, etc., the penalty for each succeeding day being ₹ 50\displaystyle 50 more than for the preceding day. How much money the contractor has to pay as penalty, if he has delayed the work by 30\displaystyle 30 days?
    NCERT’s answer
    ₹ $\displaystyle 27750$

    Working being prepared

  6. Exercise 16

    A sum of ₹ 700\displaystyle 700 is to be used to give seven cash prizes to students of a school for their overall academic performance. If each prize is ₹ 20\displaystyle 20 less than its preceding prize, find the value of each of the prizes.
    NCERT’s answer
    Values of the prizes (in ₹) are $\displaystyle 160$, $\displaystyle 140$, $\displaystyle 120$, $\displaystyle 100$, $\displaystyle 80$, $\displaystyle 60$, 40.

    Working being prepared

  7. Exercise 17

    In a school, students thought of planting trees in and around the school to reduce air pollution. It was decided that the number of trees, that each section of each class will plant, will be the same as the class, in which they are studying, e.g., a section of Class I will plant 1\displaystyle 1 tree, a section of Class II will plant 2\displaystyle 2 trees and so on till Class XII. There are three sections of each class. How many trees will be planted by the students?
    NCERT’s answer
    $\displaystyle 234$

    Working being prepared

  8. Exercise 18

    A spiral is made up of successive semicircles, with centres alternately at A and B, starting with centre at A, of radii 0.5\displaystyle 0.5 cm, 1.0\displaystyle 1.0 cm, 1.5\displaystyle 1.5 cm, 2.0\displaystyle 2.0 cm, ... as shown in Fig. 5.4. What is the total length of such a spiral made up of thirteen consecutive semicircles? (\displaystyle \left(\right. Take π=227)\displaystyle \left.\pi=\frac{22}{7}\right) [Hint : Length of successive semicircles is l1,l2,l3,l4,\displaystyle l_{1}, l_{2}, l_{3}, l_{4}, \ldots with centres at A,B,A,B,\displaystyle \mathrm{A}, \mathrm{B}, \mathrm{A}, \mathrm{B}, \ldots, respectively.]NCERT_Question_Class10_Maths_Ch5_Ex5-3_Q18
    NCERT’s answer
    $\displaystyle 143$ cm

    Working being prepared

  9. Exercise 19

    200\displaystyle 200 logs are stacked in the following manner: 20\displaystyle 20 logs in the bottom row, 19\displaystyle 19 in the next row, 18\displaystyle 18 in the row next to it and so on (see Fig. 5.5\displaystyle 5.5). In how many rows are the 200\displaystyle 200 logs placed and how many logs are in the top row?NCERT_Question_Class10_Maths_Ch5_Ex5-3_Q19
    NCERT’s answer
    $\displaystyle 16$ rows, $\displaystyle 5$ logs are placed in the top row. By putting $\displaystyle \mathrm{S}=200, a=20, d=-1$ in the formula $\displaystyle \mathrm{S}=\frac{n}{2}[2 a+(n-1) d]$, we get, $\displaystyle 41 n-n^{2}=400$. On solving, $\displaystyle n=16,25$. Therefore, the number of rows is either $\displaystyle 16$ or 25. $\displaystyle a_{25}=a+24 d=-4$ i.e., number of logs in 25th row is - $\displaystyle 4$ which is not possible. Therefore $\displaystyle n=25$ is not possible. For $\displaystyle n=16, a_{16}=5$. Therefore, there are $\displaystyle 16$ rows and $\displaystyle 5$ logs placed in the top row.

    Working being prepared

  10. Exercise 20

    In a potato race, a bucket is placed at the starting point, which is 5\displaystyle 5 m from the first potato, and the other potatoes are placed 3\displaystyle 3 m apart in a straight line. There are ten potatoes in the line (see Fig. 5.6\displaystyle 5.6). A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and she continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to run? [Hint : To pick up the first potato and the second potato, the total distance (in metres) run by a competitor is 2×5+2×(5+3)\displaystyle 2 \times 5+2 \times(5+3) ]NCERT_Question_Class10_Maths_Ch5_Ex5-3_Q20
    NCERT’s answer
    370m

    Working being prepared